Class 11 | Biological Classification [Part 02] (NEET PYQs) | Chapter 02 | BIOLOGY

 

 Class 11

Biology                    Chapter 02

Biological Classification (NEET PYQs) 

(Part 02)

 Welcome back to ExamsPoint Notes, your trusted platform for JEE, NEET, and Board exam
 Here you will get the Last 33 Years  Questions for neet Biology all Chapters
















Join our Whatsapp Channel




📼 Watch the Video Lecture

📓 Visit our YouTube Channel for a detailed visual explanation:
👉 CLICK HERE


📅 Download Full PDF Notes

📌 Get the full set of handwritten notes in PDF format on Telegram:
👉 JOIN TELEGRAM


📧 Request a Chapter

📩 DM us your requests on Instagram:
👉 @examspointnotes


🌐 Follow ExamsPoint Notes

Stay updated with the latest handwritten content:


© 2025 ExamsPoint Notes – Handwritten Notes & PYQs for JEE | NEET | CBSE








Class 11 | Biological Classification [Part 01] (NEET PYQs) | Chapter 02 | BIOLOGY

 Class 11

Biology                    Chapter 02

Biological Classification (NEET PYQs) 

(Part 01)

 Welcome back to ExamsPoint Notes, your trusted platform for JEE, NEET, and Board exam
 Here you will get the Last 33 Years  Questions for neet Biology all Chapters

 










Join our Whatsapp Channel




































📼 Watch the Video Lecture

📓 Visit our YouTube Channel for a detailed visual explanation:
👉 CLICK HERE


📅 Download Full PDF Notes

📌 Get the full set of handwritten notes in PDF format on Telegram:
👉 JOIN TELEGRAM


📧 Request a Chapter

📩 DM us your requests on Instagram:
👉 @examspointnotes


🌐 Follow ExamsPoint Notes

Stay updated with the latest handwritten content:


© 2025 ExamsPoint Notes – Handwritten Notes & PYQ for JEE | NEET | CBSE

Class 11 | The Living World [Part 01] (NEET PYQs) | Chapter 01 | BIOLOGY

 

 Class 11

Biology                    Chapter 01

THE LIVING WORLD (NEET PYQs)

(Part 01)

 Welcome back to ExamsPoint Notes, your trusted platform for JEE, NEET, and Board exam
 Here you will get the Last 33 Years  Questions for neet Biology all Chapters































Join our Whatsapp Channel










Watch the Video Lecture

📓 Visit our YouTube Channel for a detailed visual explanation:
👉 CLICK HERE


📅 Download Full PDF Notes

📌 Get the full set of handwritten notes in PDF format on Telegram:
👉 JOIN TELEGRAM


📧 Request a Chapter

📩 DM us your requests on Instagram:
👉 @examspointnotes


🌐 Follow ExamsPoint Notes

Stay updated with the latest handwritten content:


© 2025 ExamsPoint Notes – Handwritten Notes & PYQ for JEE | NEET | CBSE


The Solid States (Part-4) Handwritten Notes and Explanation| Chemistry Class-12 Chapter-1

📘 Class 12 – Chemistry

Chapter 01: The Solid State ⚪

📌 PART – 4


Welcome to Part 4 of The Solid State chapter from ExamsPoint Notes, where we focus on voids, types of interstitial sites, and the role of radius ratios in determining ionic structure and stability. These concepts are foundational in solid-state chemistry and materials science.




🔍 Topics Covered in This Video (Solid State – Part 4):

Voids / Interstitial Sites

In crystalline solids, atoms or ions are not always packed perfectly; gaps exist between them. These empty spaces are called voids or interstitial sites. They play a significant role in determining the physical properties of solids, including density, ionic conductivity, and stability.

Voids are crucial in the formation of interstitial compounds, where smaller atoms or ions occupy these gaps. Understanding voids is especially important in studying alloys and ionic crystals.


Types of Voids – Trigonal, Tetrahedral, Octahedral

There are mainly three types of voids formed during the packing of spheres:

  • Trigonal Voids: Formed when three spheres are in contact, creating a small triangular space.

  • Tetrahedral Voids: Formed when a sphere is placed in the depression of three touching spheres. Four spheres form the corners of a tetrahedron around the void.

  • Octahedral Voids: Formed when two layers of spheres are placed such that a void lies between six surrounding spheres.

The number of tetrahedral voids is double the number of atoms, while the number of octahedral voids is equal to the number of atoms in a close-packed structure.


Radius Ratio

The radius ratio is the ratio of the radius of the smaller ion (usually a cation) to that of the larger ion (anion). It helps in predicting the type of void a cation can occupy in a crystal structure:

Radius Ratio = r+ / r-

Depending on the ratio, the geometry of the resulting ionic structure varies. For example:

  • 0.225 to 0.414: Tetrahedral voids

  • 0.414 to 0.732: Octahedral voids

  • 0.732 to 1.0: Cubic voids


Conditions for Ionic Stability

For a stable ionic crystal:

  • The radius ratio must fall within certain limits so that the cation fits perfectly in the void.

  • There must be strong electrostatic attraction between oppositely charged ions.

  • Lattice energy should be high to overcome repulsive forces.

Ionic compounds with unsuitable radius ratios tend to distort or form unstable lattices. Hence, radius ratio is a key factor in determining coordination number and geometry.


Calculating Radius Ratio

To calculate the radius ratio:

  1. Identify the radii of the cation (r+) and anion (r-).

  2. Use the formula: Radius Ratio = r+ / r-

Example: For Na+ (95 pm) and Cl- (181 pm):
Radius Ratio = 95 / 181 ≈ 0.524 ➔ Octahedral void

This calculation helps predict the most probable structure type and coordination number in ionic crystals.


🖝 Watch the Video Lecture

📚 Check out the complete visual explanation on our YouTube Channel:
👉 CLICK HERE


📥 Download Full PDF Notes

📌 Join our Telegram channel to access all handwritten notes in PDF format:
👉 JOIN TELEGRAM


📧 Want Notes for Another Chapter?

📩 DM us on Instagram and let us know which chapter you want next:
👉 Instagram - @examspointnotes


🌐 Follow ExamsPoint Notes

Stay connected on all platforms:


© 2025 ExamsPoint Notes – Handwritten Notes for JEE | NEET | CBSE

The Solid States (Part-3) Handwritten Notes and Explanation| Chemistry Class-12 Chapter-1

 

📘 Class 12 – Chemistry

Chapter 01: The Solid State ⚪

📌 PART – 3


Welcome back to ExamsPoint Notes, your trusted platform for JEE, NEET, and Board exam handwritten content! This is Part 3 of Class 12 Chemistry Chapter 1: The Solid State, where we explore important concepts like density, packing efficiency, and close packing of solids.




🔍 Topics Covered in This Video (Solid State – Part 3):

Density of Unit Cell

The density of a crystalline solid is calculated using its unit cell properties. The formula used is:

Density (ρ) = (Z × M) / (a^3 × N_A)

Where:

  • Z = Number of atoms per unit cell

  • M = Molar mass

  • a = Edge length of the unit cell

  • N_A = Avogadro's number

By plugging values into this equation, students can determine the theoretical density of metals and other solids. This helps in comparing theoretical and experimental data and understanding void spaces in the lattice.


Packing Efficiency / Packing Fraction

Packing efficiency refers to the percentage of total space occupied by particles in a unit cell. It highlights how tightly atoms are packed:

  • Simple Cubic (SC): 52.4%

  • Body-Centered Cubic (BCC): 68%

  • Face-Centered Cubic (FCC)/Hexagonal Closed Packing (HCP): 74%

Higher efficiency means lesser void space, making the structure more stable. This concept is significant for comparing different types of unit cells in real-world applications.


Percentage Packing

This is essentially the same as packing efficiency. It indicates how much volume in a crystal is actually occupied by particles, with the rest being empty space (voids). FCC structures, for example, have the highest packing percentage of 74%, which explains their presence in many metals.


Closed Packed vs Loosely Packed Structures

  • Closed Packed Structures have the highest packing efficiency and minimal voids. Examples include FCC and HCP arrangements.

  • Loosely Packed Structures, like SC, have large voids and lower density.

This comparison is important in material science to predict properties like hardness, strength, and conductivity.


Classification of Close-Packed Structures (CPS)

CPS are categorized based on dimensions:

  • 1D Close Packing: Atoms are arranged in a single line touching each other.

  • 2D Close Packing:

    • Square Packing: Rows and columns aligned. Efficiency ~52%.

    • Hexagonal Packing: Each sphere surrounded by six others. Efficiency ~60%.

  • 3D Close Packing:

    • Hexagonal Close Packing (HCP): ABABAB... layer sequence.

    • Cubic Close Packing (CCP/FCC): ABCABC... layer sequence.

Understanding these arrangements explains why certain solids are more compact and stable than others.


🖝 Watch the Video Lecture

📚 Check out the complete visual explanation on our YouTube Channel:
👉 CLICK HERE


📥 Download Full PDF Notes

📌 Join our Telegram channel to access all handwritten notes in PDF format:
👉 JOIN TELEGRAM


📧 Want Notes for Another Chapter?

📩 DM us on Instagram and let us know which chapter you want next:
👉 Instagram - @examspointnotes


🌐 Follow ExamsPoint Notes

Stay connected on all platforms:


© 2025 ExamsPoint Notes – Handwritten Notes for JEE | NEET | CBSE

The Solid States (Part-2) Handwritten Notes and Explanation| Chemistry Class-12 Chapter-1

📘 Class 12 – Chemistry

Chapter 01: The Solid State ⚪

📌 PART – 2


Welcome back to ExamsPoint Notes, your trusted platform for JEE, NEET, and Board exam handwritten content! This is Part 2 of Class 12 Chemistry Chapter 1: The Solid State, where we dive deeper into the structure and geometry of crystalline solids.




📂 Contents Covered:

Location of Atoms in Unit Cells

Understanding the location of atoms within unit cells is foundational to the study of solid-state chemistry. A unit cell is the smallest repeating structural unit of a crystal lattice and determines the macroscopic physical properties of the crystal. Atoms in a unit cell may occupy corners, face centers, edge centers, or body centers, depending on the type of unit cell.

  • In a Simple Cubic (SC) unit cell, atoms are positioned only at the eight corners of the cube. Each corner atom is shared among eight neighboring cubes, contributing 1/8 of each atom to the unit cell, resulting in 1 atom per unit cell.

  • A Body-Centered Cubic (BCC) structure has atoms at all eight corners and a single atom at the center of the cube. Corner atoms contribute 1 atom, and the center atom contributes 1 full atom, totaling 2 atoms per unit cell.

  • A Face-Centered Cubic (FCC) structure includes atoms at each of the corners and at the centers of all six faces. Each face-centered atom is shared between two unit cells, and corners as usual contribute 1 atom in total, giving a total of 4 atoms per unit cell.

  • End-Centered Cubic (ECC) unit cells have atoms at each corner and at the centers of two opposite faces, contributing 1 + 2 x 1/2 = 2 atoms per unit cell.

The specific location of atoms impacts the coordination number (number of nearest neighbors), atomic packing factor (APF), and density of the material. These unit cell structures play an essential role in determining the behavior of metals, ionic solids, and other crystalline substances.


Bravais Lattices

The Bravais lattices describe the 14 unique three-dimensional arrangements in which atoms can be systematically placed to form a crystal. These lattices form the framework for all crystalline materials and are grouped into 7 distinct crystal systems, each with specific geometric parameters and angles. The 7 crystal systems include:

  1. Cubic

  2. Tetragonal

  3. Orthorhombic

  4. Monoclinic

  5. Triclinic

  6. Hexagonal

  7. Rhombohedral (Trigonal)

Each of these systems can exhibit one or more of the four types of Bravais lattices: primitive (P), body-centered (I), face-centered (F), and end-centered (C). For example, the cubic system includes three Bravais lattices: simple cubic, body-centered cubic, and face-centered cubic.

Bravais lattices form the fundamental backbone of crystal structures, enabling chemists and material scientists to analyze symmetry, predict physical properties, and categorize materials. Understanding these structures is key to interpreting X-ray diffraction patterns, designing materials with specific properties, and studying phase transitions.


Characteristics of Unit Cells

Unit cells are categorized based on their atomic arrangement into primitive and non-primitive types. A primitive unit cell contains atoms only at the corners of the unit cell. Since each corner atom is shared among eight adjacent unit cells, each contributes 1/8 of an atom, totaling 1 atom per primitive unit cell.

On the other hand, non-primitive unit cells have atoms at additional positions such as the center of the body (body-centered), the centers of the faces (face-centered), or the centers of edges. These additional atoms increase the number of atoms per unit cell and affect the density and packing efficiency.

Another characteristic of unit cells is the coordination number, which indicates the number of nearest neighbors an atom has. For example, SC has a coordination number of 6, BCC has 8, and FCC has 12.

The atomic packing factor (APF), which measures how tightly atoms are packed in a unit cell, also varies with the type: SC has 52.4%, BCC 68%, and FCC the highest at 74%. These characteristics determine the material's mechanical properties, such as hardness, ductility, and tensile strength.


Rank (Z) of a Crystal

The Rank (Z) of a crystal represents the number of atoms per unit cell. It is a critical parameter used in calculating various physical properties like the density of the solid. The Z value differs for different types of unit cells:

  • Simple Cubic (SC): Z = 1

  • Body-Centered Cubic (BCC): Z = 2

  • Face-Centered Cubic (FCC): Z = 4

Knowing the rank is essential for determining the mass of the unit cell, which is calculated as:

Mass of unit cell=Z×M/NA\text{Mass of unit cell} = Z \times M / N_A

Where:

  • ZZ is the number of atoms per unit cell

  • MM is the molar mass

  • NAN_A is Avogadro’s number

This value is then used to compute the density using:

Density=Mass of unit cella3\text{Density} = \frac{\text{Mass of unit cell}}{a^3}

Where aa is the edge length of the unit cell.


Relationships between Edge Length (a), Radius (r), and Interplanar Distance (d)

The edge length aa, atomic radius rr, and interplanar distance dd are interrelated through geometric equations derived from the unit cell structures. These formulas vary based on the type of unit cell:

  • SC: a=2ra = 2r

  • BCC: a=4r3a = \frac{4r}{\sqrt{3}}

  • FCC: a=4r2a = \frac{4r}{\sqrt{2}}

These relationships are critical for solving problems involving atomic size, unit cell volume, and X-ray diffraction. Interplanar distances are especially important in Bragg’s Law for analyzing crystal structure.

For example, in an FCC structure, atoms are in contact along the face diagonal, which is 2a\sqrt{2}a. Setting this equal to 4r (2 radii per atom, 2 atoms per diagonal) yields a=4r2a = \frac{4r}{\sqrt{2}}.

Knowing these formulas allows for accurate calculations of atomic radius, density, and other structural parameters essential in materials science and physical chemistry.


📖 Revision Questions

  1. What is the number of atoms in a BCC unit cell?

  2. Define a Bravais lattice. How many types of Bravais lattices are possible?

  3. Derive the formula connecting atomic radius and edge length for an FCC unit cell.

  4. What is the Rank (Z) for a simple cubic structure?

  5. Explain the distinction between primitive and non-primitive unit cells.


📼 Watch the Video Lecture

📓 Visit our YouTube Channel for a detailed visual explanation:
👉 CLICK HERE


📅 Download Full PDF Notes

📌 Get the full set of handwritten notes in PDF format on Telegram:
👉 JOIN TELEGRAM


📧 Request a Chapter

📩 DM us your requests on Instagram:
👉 @examspointnotes


🌐 Follow ExamsPoint Notes

Stay updated with the latest handwritten content:


© 2025 ExamsPoint Notes – Handwritten Notes for JEE | NEET | CBSE

The Solid States (Part-1) Handwritten Notes and Explanation| Chemistry Class-12 Chapter-1

📘 Class 12 – Chemistry

Chapter 01: The Solid State ⚪

📌 PART – 1


Welcome to ExamsPoint Notes, your trusted platform for JEE, NEET, and Board exam handwritten content! This is the first part of Class 12 Chemistry Chapter 1: The Solid State. Dive deep into the structure, properties, and classification of solids with crystal-clear concepts.




📂 Contents Covered:

States of Matter

Matter exists in three primary states: solid, liquid, and gas. Each state has unique characteristics defined by the arrangement and movement of particles. Solids are the most rigid and ordered form of matter, characterized by closely packed particles arranged in a definite pattern. This arrangement results in a fixed shape and volume. Liquids have a definite volume but no fixed shape, and their particles are less tightly packed, allowing fluidity. Gases, on the other hand, neither have fixed shape nor volume, and their particles are in constant, random motion. Understanding these states is essential as it lays the foundation for differentiating solids and studying their specialized properties in detail.


What is Solid & its Properties

Solids are one of the fundamental states of matter, characterized by a definite shape and volume. This is due to the strong intermolecular forces and minimal intermolecular space between their constituent particles. Solids are rigid, meaning they retain their shape when subjected to external forces, unlike liquids or gases. They are also incompressible because their particles are closely packed. Additionally, solids resist shearing forces and have high density. Properties such as high melting and boiling points, electrical and thermal conductivity (in metals), and structural integrity make solids vital in both natural and industrial contexts.


Classification of Solids

Solids are broadly classified into crystalline and amorphous based on the arrangement of their constituent particles.

  • Crystalline Solids have a highly ordered three-dimensional arrangement. They have sharp melting points and definite heat of fusion. Examples include salt, quartz, and diamond.

  • Amorphous Solids lack long-range order, and their particles are randomly arranged. They do not have a sharp melting point and soften over a range of temperatures. Examples include glass, rubber, and plastics.

This classification is important for understanding the mechanical and thermal behavior of different materials in chemistry and materials science.


Anisotropic & Isotropic Substances

These terms refer to how a substance behaves when observed from different directions.

  • Anisotropic materials exhibit different physical properties (like refractive index or electrical conductivity) in different directions. Crystalline solids, due to their ordered structure, often show anisotropy.

  • Isotropic materials have the same properties in all directions, a characteristic commonly seen in amorphous solids and liquids.

Anisotropy is a key diagnostic feature for identifying crystalline substances in material science and crystallography.


Polymorphism

Polymorphism is the phenomenon where a substance can exist in more than one crystalline form, each with different physical properties such as melting point and density. A classic example is carbon, which exists both as diamond (a hard, transparent insulator) and graphite (a soft, opaque conductor). Polymorphism is not only significant in chemistry but also in pharmaceuticals, where different polymorphs of the same compound can have varied bioavailability and stability.


Crystalline vs Amorphous Solids

Feature Crystalline Solids Amorphous Solids
Structure Long-range order Short-range order
Melting Point Sharp Gradual
Heat of Fusion Definite Indefinite
Anisotropy Yes No
Examples NaCl, Quartz Glass, Rubber

This comparison helps in determining the applications and behavior of different materials.


Cooling Curves of Solids

Cooling curves plot temperature vs. time during the cooling of a substance.

  • In crystalline solids, the curve shows a plateau where the temperature remains constant during the phase change (solidification), indicating a sharp melting/freezing point.

  • In amorphous solids, the temperature drops continuously without a distinct plateau, reflecting a gradual softening process.

These curves are useful for understanding thermal transitions and purity of materials.


Polycrystalline Solids

Polycrystalline materials consist of numerous small crystals (grains), each oriented differently. Though individual grains are crystalline, the overall material may appear isotropic if the grains are randomly oriented. Metals, ceramics, and some polymers are polycrystalline. These solids strike a balance between crystalline order and mechanical robustness, making them ideal for construction, manufacturing, and electronics.


🖝 Watch the Video Lecture

📚 Check out the complete visual explanation on our YouTube Channel:
👉 CLICK HERE


📥 Download Full PDF Notes

📌 Join our Telegram channel to access all handwritten notes in PDF format:
👉 JOIN TELEGRAM


📧 Want Notes for Another Chapter?

📩 DM us on Instagram and let us know which chapter you want next:
👉 Instagram - @examspointnotes


🌐 Follow ExamsPoint Notes

Stay connected on all platforms:


© 2025 ExamsPoint Notes – Handwritten Notes for JEE | NEET | CBSE